derive formula for vertical displacement of an electron when entered in a uniform electrical field with initial velocity vo also find the angle to which it emerged from electrical field
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Answer:
Since, no field and hence no force act on the electron along X-direction.
Hence, v
x
remains constant.
Now, time taken to get out of field=t=
v
x
l
⟹t=
3×10
6
0.1
⟹t=3.33×10
−8
s
Acceleration of electron=
a
=
m
F
=
m
−e
E
⟹
a
=
9.1×10
−31
1.6×10
−19
×200
(−
j
^
)
⟹a=−3.51×10
13
j
^
m/s
2
Now, initial velocity along y-axis=0
y=u
y
t+
2
1
a
y
t
2
⟹y=0−
2
1
×3.51×10
13
×(3.33×10
−8
)
2
⟹y=−1.95×10
−2
m
⟹y=−1.95cm
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