Derive Formula from the statement " Rate of change of momentum is directly proportional to force "
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Answered by
7
Hey there!
Given rate of change of momentum is directly proportional to its Force applied.
First of all
Momentum =P = mv
Rate of change of velocity = Pf - Pi /t
Here Pi is the initial momentum,
Pf is the final momentum
now
Pf - Pi /t ∝F
mv- mu /t ∝ F
we know that final and initial velocities are considered v,u respectively.
m( v - u)/t ∝F
F ∝ ma
here we take acceleration = v-u/t
So for removing proportionality I am introducing a proportionality constant Say K
finally F= maK
here K =1
Finally F = m* a
Force is the product of the mass of the object and acceleration produced.
hope helped!
Given rate of change of momentum is directly proportional to its Force applied.
First of all
Momentum =P = mv
Rate of change of velocity = Pf - Pi /t
Here Pi is the initial momentum,
Pf is the final momentum
now
Pf - Pi /t ∝F
mv- mu /t ∝ F
we know that final and initial velocities are considered v,u respectively.
m( v - u)/t ∝F
F ∝ ma
here we take acceleration = v-u/t
So for removing proportionality I am introducing a proportionality constant Say K
finally F= maK
here K =1
Finally F = m* a
Force is the product of the mass of the object and acceleration produced.
hope helped!
Answered by
3
hii dear friend
formula
mometntum is to directly proportional
ACCORDING TO Newton 2nd law
lets see
initial momentum of the body = MU
final momentum of the body = mv
cheng in momentum = mu - mv
lets see
= mu-mv/ t
= M (V- U ) /t
= Ma [ Q a = v-u/t ]
..............
And direct to force
F= Ma or Fa = k ma
its depend on unit..
formula
mometntum is to directly proportional
ACCORDING TO Newton 2nd law
lets see
initial momentum of the body = MU
final momentum of the body = mv
cheng in momentum = mu - mv
lets see
= mu-mv/ t
= M (V- U ) /t
= Ma [ Q a = v-u/t ]
..............
And direct to force
F= Ma or Fa = k ma
its depend on unit..
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