Question

derive formulae of k.E​

Answer 1

Answer:

W=Fs

v square -u square=2as,s=Vsquare/2a

F=ma, W=ma, V square/2a

W=KE=mvsqu./2=1/2 mv squ.

Answer 2

$\boxed{\huge\mathfrak{ \red{ \bold{ derivation \: of \: kinetic \: energy}}}}$

Let an object of mass 'm' having u=0 ,when force is applied on the object and acceleration 'a' is created on the object :

As we know that ,

$\boxed{ \green{\huge{v}^{2} - {u}^{2} = 2as}}$

Here , u =0

and

Multiply both sides by 'm' we get,

$\leadsto \: {v}^{2} m = 2ams$

We know that , F=ma

$\leadsto \: {v}^{2} m = 2fs \\ \\ \leadsto \: \frac{1}{2} m {v}^{2} = f.s$

Again we know that ,

$\boxed{ \blue{ \bold {\: w = f.s }}}$

$\leadsto w \: = \frac{1}{2}m {v}^{2}$

OR ,

K.E =

$\boxed{ \purple{\bold{ \frac{1}{2} m {v}^{2} }}}$