Chemistry, asked by sridhanjit826, 4 months ago

Derive Graham's law of diffusion in terms of molar mass of gases.

Answers

Answered by shivamtripathi885
0

i don't know answer of this question

Explanation:

i don't know answer of this question because I am the player of free fire

Answered by Key08
2

Answer:

Graham's law of diffusion was formulated by Scottish physical chemist Thomas Graham in 1848. Graham found experimentally that the rate of diffusion of a gas is inversely proportional to the square root of the mass of its particles. the formula can be written as:

Rate1/Rate2 = √M2/M1

Explanation:

where:

rate1 is the rate of diffusion for the first gas. (volume on number of moles per unit time). Rate2 is the rate of diffusion for the second gas.

m1 is the molar mass of gas 1.

m2 is the molar mass of gas 2.

hope this answer helps you, if it helps you then please thank me and Mark my answer as brainliest.

Similar questions