DERIVE GRAPHICALLLY S=UT+1/2 at2
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displacement =intial speed x time +1/2 at square right
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⭐ NOTE :
Refer the attachment!
EQUATION DESCRIBING THE RELATION BETWEEN DISPLACEMENT AND TIME.
Let us suppose that an object in unform acceleration 'a' and it has covered the distance 's' within time't'. From the graph in figure 1.9 , the distance covered by the object during time 't' is given by the area of quadrangle DOEB.
: . s=area of quadrangle DOEB
=area(rectangle DOEA) +area of triangle (DAB)
: . s=(AE×OE) +(1/2×[AB×DA])
But, AE =u, OE= t and (OE=DA= t)
AB=at............. (AB=CD)
: . s=u×t+1/2×at×t
: . Newton's second equation of motion is
s=ut +1/2at²
HENCE, DERIVED!
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