Derive Graphically,
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Answer:
TO DERIVE :
SOLUTION :
• The distance travelled is the area of the shaded portion.
area of CDFG + area of BCDE
→ Area of CDFG + area of ADE - Area of ACB
→ Sn = u + [ 1/2 a(n)² - 1/2 a(n - 1)² ]
→ Sn = u + 1/2 a(2n - 1)
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