Derive graphically the equation for position-time realtion for an object travellimg a distance 's' in time 't' under uniform acceleration 'a'
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- Consider the graph shown in the given attachment. Obviously, the total distance s travelled by the object in time t is given by are under v-t graph. Obviously, OABGC is a, whose area is (OA + BC/2) × OC. Therefore, this equation is the position velocity relation for uniformly accelerated motion.
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Explanation:
It is uniformally accelaration .
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