Question

derive graphically the equation of motion for position -velocity relation of a body moving with uniform acceleration

Answer 1

from first equation of motion we get v-u/a =t

1/2 × (v-u)/a × (v+u)=S

1/2a × (v-u)(v+u)=S


$\frac{1}{2a} \times ( {v}^{2} - {u}^{2} ) = s$
${v}^{2} - {u}^{2} = 2as$

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Answer 2

Answer:

Here is the answer of the question in a simple formate

Explanation:

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