Derive graphically the equation of motion for position time relation
Answers
Explanation:
The following equations of motion are valid only when…
acceleration is constant
motion is constrained to a straight line
The equations of motion
traditional name equation relationship
1st equation v = v0 + at velocity-time
2nd equation s = s0 + v0t + ½at2 position-time
3rd equation v2 = v02 + 2a(s − s0) velocity-position
merton rule v = ½(v + v0) average velocity
where…
s0 = initial position (the position at the beginning of some event)
s = final position (the position at the end of some event)
v0 = initial velocity (the velocity at the beginning of some event)
v = final velocity (the velocity at the end of some event)
a = acceleration
t = time (the duration of the event)
Alternatively
Variation on the equations of motion
traditional name equation relationship
1st equation v = v0 + at velocity-time
2nd equation ∆s = v0t + ½at2 displacement-time
3rd equation v2 = v02 + 2a∆s velocity-displacement
merton rule v = ½(v + v0) average velocity
where…
∆s = displacement (change in position)
v0 = initial velocity
v = final velocity
a = acceleration
t = time
The signs on the spatial quantities should be…
the same if they point in the same direction
opposite if they point in opposite directions
The choice of which direction is positive and which is negative is arbitrary.
The laws of physics are isotropic (are not affected by your choice).
Make your decision and stick with it. (Be consistent.)
I think this will help you.