derive graphically the equations for positions time relation for an object travelling a distance s in time t under uniform acceleration
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Hi, I am attatching a pic to make it easier.
We know that the area of a velocity - time graph is equal to its distance.
So, s = area of the graph
The graph can be broken down to 2 pieces - a rectangle and a triangle.
∴ s = area of the rectangle + area of the triangle
Area of the rectangle = l x b
= u x t
= ut
Area of the triangle = (1/2)bh
= (1/2)(v-u)t ( (v - u)/t = a. ∴ v - u = at)
= 1/2 at x t
= 1/2 at²
∴ s = area of the rectangle + area of the triangle
s = ut + 1/2 at²
Hence Proved!
Hope it helps!
We know that the area of a velocity - time graph is equal to its distance.
So, s = area of the graph
The graph can be broken down to 2 pieces - a rectangle and a triangle.
∴ s = area of the rectangle + area of the triangle
Area of the rectangle = l x b
= u x t
= ut
Area of the triangle = (1/2)bh
= (1/2)(v-u)t ( (v - u)/t = a. ∴ v - u = at)
= 1/2 at x t
= 1/2 at²
∴ s = area of the rectangle + area of the triangle
s = ut + 1/2 at²
Hence Proved!
Hope it helps!
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