derive graphically:v²-u²=2as and s=ut +½at²
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Graph for derivation
we know : displacement = area under the velocity time graph .
S= area of trapezium ACEF
S= 1/2 ( b¹ + b² ) h
s= 1/2 ( AF+CE )FE
S= 1/2 ( U+ V) T
We know -v= u+ at
v-u/a= t
now 2 in 1
S= 1/2( v+u) (v-u)
2as= ( v+u) (v-u)
2as=v²-u²
[v² - u2 = 2as]
hope it will help u
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Refer to the attachment !!
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![](https://hi-static.z-dn.net/files/d1c/99515ea9b5f0fc388205bf41a75f3add.jpg)
![](https://hi-static.z-dn.net/files/dc1/885cbda6274901860db0ea3c7f7cbd9d.jpg)
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