Question

Derive h=0.5gt^2.........​

Answer 1

Answer:

Actually, the following formula is used more commonly:

s=ut+1/2 (at^2)

where s=displacement, a=9.8, t= time (sec), u=initial velocity(speed) of the object(ms^-1 or m/s).

You can't use h=0.5gt^2 in all cases,

It is only valid when the initial velocity of an object is 0

As,

s=ut+1/2 (at^2) (putting the 0 in place of u)

Becomes,..

s= 0 +1/2(at^2)

Which you can write further by simplifying as,

s=0.5gt^2

[NOTE: HERE h refers to height which is same as displacement in the above case]

Hope this will help you

please try to mark it as brainliest....

Answer 2

Answer:

Simplifying 0.5gt2 = h Solving 0.5gt2 = h Solving for variable 'g'. Move all terms containing g to the left, all other terms to the right. Divide each side by '0.5t2'. g = 2ht-2 Simplifying g = 2ht-2