DERIVE INVERSE SQUARE LAW.
HarishAS:
not helpful?
ok wait i will derive through another method.
Which class question ???
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I read Feynman's Lost lecture a while ago. In that spirit, I'm trying to do a more simplified version of coming up with the inverse square relation.
Using Kepler's 2nd,
A1=12r21θ1A1=12r12θ1
A2=12r22θ2A2=12r22θ2
A1=12r21ω1tA1=12r12ω1t
A2=12r22ω2tA2=12r22ω2t
mω1A1=12mr21ω21mω1A1=12mr12ω12
mω2A2=12mr22ω22mω2A2=12mr22ω22
mv1A1=12r21F1mv1A1=12r12F1
mv2A2=12r22F2mv2A2=12r22F2
Dividing one by the other, I get
F1F2=v1v2r22r21F1F2=v1v2r22r12
which is almost there, except for the v1v2v1v2
Any suggestions on how to proceed from here?
Using Kepler's 2nd,
A1=12r21θ1A1=12r12θ1
A2=12r22θ2A2=12r22θ2
A1=12r21ω1tA1=12r12ω1t
A2=12r22ω2tA2=12r22ω2t
mω1A1=12mr21ω21mω1A1=12mr12ω12
mω2A2=12mr22ω22mω2A2=12mr22ω22
mv1A1=12r21F1mv1A1=12r12F1
mv2A2=12r22F2mv2A2=12r22F2
Dividing one by the other, I get
F1F2=v1v2r22r21F1F2=v1v2r22r12
which is almost there, except for the v1v2v1v2
Any suggestions on how to proceed from here?
kr diya
ok
Ooo
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It is a law that the intensity of an effect such as illumination or gravitational force changes in reverse proportion to the square of the distance from the source.
Light intensity is proportional to 1/distance squared
Light intensity is proportional to 1/distance squared
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