Question

Derive K. E. = 1⁄2 mv2

Answer 1

Answer:

Derived

Explanation:

Let a body at rest attain a velocity v with constant acceleration a

By third equation of motion,

$v^2 = u^2 - 2 as$

Therefore,

$v^2 = 0 + 2as => s = \frac{v^2}{2a}$

Work done = $F.s$

We know,

F = ma

Substituting,

$Work = (ma).(\frac{v^2}{2a})= \frac{mv^2}{2} = \\\frac{1}{2}mv^{2}$