derive Kirchhoff's equation
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Hey Dear -
Solution-
In balanced Wheatstone's bridge, zero current flow through galvanometer. Means while applying Kirchoff's law we can neglet this path.
Look at the figure,
No current flows through galvanometer G if circuit is balanced.
Applying Kirchoff's law to
1) Mesh ABDA,
-I1R1 + (I-I1)R4 = 0
I1R1 = (I-I1)R4 ….(1)
2) Mesh BCDB,
-I1R2 + (I-I1)R3 = 0
I1R2 = (I-I1)R3 ….(2)
Dividing (1) by (2),
I1R1 / I1R2 = (I-I1)R4 / (I-I1)R3
R1/R2 = R4/R3
This is balancing condition for Wheatstone's bridge. Also known as Kirchoff's equation.
Best luck for exams buddy
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