derive law of resistance n series so as to explain equivalent resistance of circuit
Answers
Answer:
Explanation:
According to Ohm’s law, the voltage drop, V, across a resistor when a current flows through it is calculated by using the equation V=IR, where I is current in amps (A) and R is the resistance in ohms (Ω).
So the voltage drop across R1 is V1=IR1, across R2 is V2=IR2, and across R3 is V3=IR3. The sum of the voltages would equal: V=V1+V2+V3, based on the conservation of energy and charge. If we substitute the values for individual voltages, we get:
V = IR
1 + IR
2 + IR
3
or
V
=
I
(
R
1
+
R
2
+
R
3
)
This implies that the total resistance in a series is equal to the sum of the individual resistances. Therefore, for every circuit with N number of resistors connected in series:
RN
(
series
)
=
R
1
+
R
2
+
R
3
+
…
+
R
N
.
Since all of the current must pass through each resistor, it experiences the resistance of each, and resistances in series simply add up.