Question

derive laws of conversation of momentum​

Answer 1

Answer:

Derivation of Conservation of Momentum

Applying Newton's third law, these two impulsive forces are equal and opposite i.e. If the time of contact is t, the impulse of the force F21 is equal to the change in momentum of the first object. The impulse of force F12 is equal to the change in momentum of the second object.

Answer 2

Answer:

Explanation:

Consider two colliding particles A and B whose

masses are m1 and m2

with initial and final velocities as

u1 and v1 of A and u2 and v2 of B.

The time of contact between two particles is given as t.

A= m1 (v1−u1)    (change in momentum of particle A)

B= m2 (v2−u2)   (change in momentum of particle B)

F BA=−F AB        (from third law of motion)

FBA=m2∗a2

       =m2(v2−u2)t

FAB=m1∗a1

       =m1(v1−u1)t

m2 (v2−u2)t=−m1 (v1−u1)t

m1u1 + m2u2 = m1v1 + m2v2

Therefore, above is the equation of law of conservation of momentum where m1u1+m2u2 is the representation of total momentum of particles A and B before the collision and m1v1+m2v2 is the representation of total momentum of particles A and B after the collision.