Derive laws of resistance in series so as to explain equivalent resistance of
circuit ?
Answers
Answered by
7
Two or more wire connected in series with equal resistance
Three resistance R1 R2 R3 And current( I) is flowing from the each resistance And V is the potential difference between 2 ends
Suppose R1,R2,R3 as V1,V2,V3
So V=V1+V2+V3
Put Rs Is the sum of all three reistance and so by applying ohms laws V=IR
We get
V1=IR1
V2=IR2
V3=IR3
So,IRs=IR1+ IR2+ IR3
So hence proved
Rs=R1+ R2+ R3
So in this Rs is the sum of all three resistance
Ok this is your answer give me thanks and rate my answer it’s needed
Three resistance R1 R2 R3 And current( I) is flowing from the each resistance And V is the potential difference between 2 ends
Suppose R1,R2,R3 as V1,V2,V3
So V=V1+V2+V3
Put Rs Is the sum of all three reistance and so by applying ohms laws V=IR
We get
V1=IR1
V2=IR2
V3=IR3
So,IRs=IR1+ IR2+ IR3
So hence proved
Rs=R1+ R2+ R3
So in this Rs is the sum of all three resistance
Ok this is your answer give me thanks and rate my answer it’s needed
Answered by
1
Answer:
guy fugu buiplopki
v=32
Explanation:
rs=,r1+r2+re
Similar questions