derive lens and mirror formula
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lens formula
1/f=1/v - 1/u
mirror formula
1/f= 1/v + 1/u
1/f=1/v - 1/u
mirror formula
1/f= 1/v + 1/u
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Mirror formula is the relationship between object distance (u), image distance (v) and focal length.


Derivation
The figure shows an object AB at a distance u from the pole of a concave mirror. The image A1B1 is formed at a distance v from the mirror. The position of the image is obtained by drawing a ray diagram.
Consider the D A1CB1 and D ACB

[when two angles of D A1CB1 and D ACB are equal then the third angle 




But ED = AB

From equations (1) and (2)

If D is very close to P then EF = PF



But PC = R, PB = u, PB1 = v, PF = f
By sign convention
PC = -R, PB = -u, PF = -f and PB1 = -v
 Equation (3) can be written as





Dividing equation (4) throughout by uvf we get


Equation (5) gives the mirror formula
Derivation of Lens Formula (Convex Lens)
Let AB represent an object placed at right angles to the principal axis at a distance greater than the focal length f of the convex lens. The image A1B1 is formed beyond 2F2 and is real and inverted.
OA = Object distance = u
OA1 = Image distance = v
OF2 = Focal length = f
OAB and OA1B1 are similar
But we know that OC = AB
the above equation can be written as
From equation (1) and (2), we get
Dividing equation (3) throughout by uvf
Derivation of Lens Formula (Concave Lens)
Let AB represent an object placed at right angles to the principal axis at a distance greater than the focal length f of the convex lens. The image A1B1 is formed between O and F1 on the same side as the object is kept and the image is erect and virtual.
OF1 = Focal length = f
OA = Object distance = u
OA1 = Image distance = v
But from the ray diagram we see that OC = AB
From equation (1) and equation (2), we get
Dividing throughout by uvf
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Derivation
The figure shows an object AB at a distance u from the pole of a concave mirror. The image A1B1 is formed at a distance v from the mirror. The position of the image is obtained by drawing a ray diagram.
Consider the D A1CB1 and D ACB

[when two angles of D A1CB1 and D ACB are equal then the third angle 




But ED = AB

From equations (1) and (2)

If D is very close to P then EF = PF



But PC = R, PB = u, PB1 = v, PF = f
By sign convention
PC = -R, PB = -u, PF = -f and PB1 = -v
 Equation (3) can be written as





Dividing equation (4) throughout by uvf we get


Equation (5) gives the mirror formula
Derivation of Lens Formula (Convex Lens)
Let AB represent an object placed at right angles to the principal axis at a distance greater than the focal length f of the convex lens. The image A1B1 is formed beyond 2F2 and is real and inverted.
OA = Object distance = u
OA1 = Image distance = v
OF2 = Focal length = f
OAB and OA1B1 are similar
But we know that OC = AB
the above equation can be written as
From equation (1) and (2), we get
Dividing equation (3) throughout by uvf
Derivation of Lens Formula (Concave Lens)
Let AB represent an object placed at right angles to the principal axis at a distance greater than the focal length f of the convex lens. The image A1B1 is formed between O and F1 on the same side as the object is kept and the image is erect and virtual.
OF1 = Focal length = f
OA = Object distance = u
OA1 = Image distance = v
But from the ray diagram we see that OC = AB
From equation (1) and equation (2), we get
Dividing throughout by uvf
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sweety105:
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