Question

Derive magnetic force acts on a charged particle

Answer 1

Answer:

For a particle moving in a plane perpendicular to external magnetic field we know that:

F = qvBsinθ = mv^2/r

or

F = mv^2r^-1

thus,

r^n = r^-1

or

n = -1

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OR

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When a charge particle is projected with velocity v perpendicular to the magnetic field,B, the force due to field is

F = q(vXB), where q is charge of particle. This force is perpendicular to B and v. This fact shows that the particle is moving on circular path in the field. In this situation the magnetic force provides the centripetal force necessary for circular motion. Therefore ,

mv^2/r=qvB.

If we stop here, then n=-1. But, if we write mv^2/r=mrw^2, then n =1.

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Explanation:

Answer 2

THEORY

From Newton's second law of motion on the particle is the force exerted by the magnetic field, this magnetic field force must be the net force.Forces by magnetic fields on moving charged particles always act in a direction that is perpendicular to the velocity of the particle, meaning that they will never change the speed of the particle.Since in this case the particle is experiencing a net force, the particle must be accelerating.All of the vector quantities here are constantly changing since the particle is constantly changing direction.The velocity direction is changing, the acceleration direction is changing, the momentum direction is changing along with the velocity, and the position is obviously changing.The particle's speed does not change therefore option "C" is right.