derive mayor's formula
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5
⭕️let one gram mole of ideal gas enclosed in cyclinder fitted with piston frictionless then P,V,T== initial pressure,volume and temperature of the gas respectively.
✔️✔️✔️Derivation :-
✔️✔️Use the first law of thermodynamics
dQ=dU + pdv
✔️✔️specific heat of a gas at constant volume
Cv = (dQ / dT)v
Cv = dU / dT ➖➖➖➖➖➖➖➖[1]
✔️✔️specific heat capacity at constant pressure
Cp = (dQ / dT)p
Cp = dU + Pdv / dT
Cp = dU / dT + P(dV / dT)
Cp = Cv + Pdv / dT (using 1st) ➖➖➖➖[2]
By applying ideal gas in [1] for 1 mole
PV = nRT
PV = (1)RT
PV = RT
P dv / dt = R dT / dt
Pdv = RdT
P(dv / dT) =R
Putting in [2] we get;
Cp - Cv = R.
proved !!!
✔️✔️✔️Derivation :-
✔️✔️Use the first law of thermodynamics
dQ=dU + pdv
✔️✔️specific heat of a gas at constant volume
Cv = (dQ / dT)v
Cv = dU / dT ➖➖➖➖➖➖➖➖[1]
✔️✔️specific heat capacity at constant pressure
Cp = (dQ / dT)p
Cp = dU + Pdv / dT
Cp = dU / dT + P(dV / dT)
Cp = Cv + Pdv / dT (using 1st) ➖➖➖➖[2]
By applying ideal gas in [1] for 1 mole
PV = nRT
PV = (1)RT
PV = RT
P dv / dt = R dT / dt
Pdv = RdT
P(dv / dT) =R
Putting in [2] we get;
Cp - Cv = R.
proved !!!
Answered by
3
Mayers formula:
Cp - Cv = R
Derivation:
ΔU = ΔQ + ΔW
ΔU = Cv ΔT (At pressure is constant)
ΔQ = Cp ΔT (At pressure is constant)
ΔW = -P ΔV (Negative since the calculation been complete)
Pv = RT (1 mole of gas)
Because of pressure is constant, R is also constant
Change in V will make change in T
PΔV = R ΔT
Cv ΔT = CpΔT - RΔT
Divided by ΔT
Cv = Cp - R
R is Subject
Cp - Cv = R
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Cp - Cv = R
Derivation:
ΔU = ΔQ + ΔW
ΔU = Cv ΔT (At pressure is constant)
ΔQ = Cp ΔT (At pressure is constant)
ΔW = -P ΔV (Negative since the calculation been complete)
Pv = RT (1 mole of gas)
Because of pressure is constant, R is also constant
Change in V will make change in T
PΔV = R ΔT
Cv ΔT = CpΔT - RΔT
Divided by ΔT
Cv = Cp - R
R is Subject
Cp - Cv = R
please..
don't forget to follow...
mark as brainlist...
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