Physics, asked by Anonymous, 8 months ago

derive momentum operator?

Answers

Answered by aswothaa

1

Answer:

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Explanation:

Momentum operator...Okkk

Answered by Anonymous

2

Answer:

In a basis of Hilbert space consisting of momentum eigenstates expressed in the momentum representation, the action of the operator is simply multiplication by p, i.e. it is a multiplication operator, just as the position operator is a multiplication operator in the position representation.

Explanation:

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