Derive Nernst equation of a electrochemical cell.
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Answered by
4
hey friend
here is the answr=====
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FIRSTLY WHAT IS NERNST EQUATION
..
The Nernst equation is used to calculate the voltage of an electrochemical cell.or the conc. of any component.
________________
NOW ,FORMULA AND SOME GENERAL SYMBOLS USED IN IT
Ecell = E0cell - (RT/nF)lnQ
Ecell = cell potential under nonstandard conditions (V)
E0cell = cell potential under standard conditions
R = gas constant, which is 8.31 (volt-coulomb)/(mol-K)
T = temperature (K)
n = number of moles of electrons exchanged in the electrochemical reaction (mol)
F = Faraday's constant, 96500 coulombs/mol
Q = reaction quotient, which is the equilibrium expression with initial
concentrations rather than equilibrium concentrations
Ecell = E0cell - (2.303*RT/nF)logQ
at 298K, Ecell = E0cell - (0.0591 V/n)log Q
=================================
hope it hlps
THANX
BE BRAINLY....
FOLLOW ME
here is the answr=====
=======================
FIRSTLY WHAT IS NERNST EQUATION
..
The Nernst equation is used to calculate the voltage of an electrochemical cell.or the conc. of any component.
________________
NOW ,FORMULA AND SOME GENERAL SYMBOLS USED IN IT
Ecell = E0cell - (RT/nF)lnQ
Ecell = cell potential under nonstandard conditions (V)
E0cell = cell potential under standard conditions
R = gas constant, which is 8.31 (volt-coulomb)/(mol-K)
T = temperature (K)
n = number of moles of electrons exchanged in the electrochemical reaction (mol)
F = Faraday's constant, 96500 coulombs/mol
Q = reaction quotient, which is the equilibrium expression with initial
concentrations rather than equilibrium concentrations
Ecell = E0cell - (2.303*RT/nF)logQ
at 298K, Ecell = E0cell - (0.0591 V/n)log Q
=================================
hope it hlps
THANX
BE BRAINLY....
FOLLOW ME
Answered by
2
Explanation:
The Nernst equation relates the effective concentrations ( activities ) of the components of a cell reaction to the standard cell potential. For a simple reduction of the form Mn+ + ne– → M, it tells us that a half-cell potential will change by 59/n mV per 10-fold change in the activity of the ion.
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