Derive Newton's third law from second law
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Newton's third law of motion :Every action has an equal and opposite reaction...
Derivation :
Consider an isolated system of two bodies A and B.An isolated system means where there is no external force acting..
Now let F be the force acting on B by A and F be the force acting on A and B..
Now, Rate of Change of momentum of A =dpB/dt
Thus,FAB=dpB/dt ...equation no.1..
FBA=dpA/dt..equation no.2..
By adding 1 and 2..we get....
FAB+FBA = dpB/dt + dpA/dt = d(pB+pA)
But if no force is applied momentum will be '0'bcoz no velocity will be there so rate of change of momentum will also be '0'..
so,d(pA+pB)/dt =0
FAB +FBA=0
or..
FAB= -FBA
please mark it as brain liest answer
Derivation :
Consider an isolated system of two bodies A and B.An isolated system means where there is no external force acting..
Now let F be the force acting on B by A and F be the force acting on A and B..
Now, Rate of Change of momentum of A =dpB/dt
Thus,FAB=dpB/dt ...equation no.1..
FBA=dpA/dt..equation no.2..
By adding 1 and 2..we get....
FAB+FBA = dpB/dt + dpA/dt = d(pB+pA)
But if no force is applied momentum will be '0'bcoz no velocity will be there so rate of change of momentum will also be '0'..
so,d(pA+pB)/dt =0
FAB +FBA=0
or..
FAB= -FBA
please mark it as brain liest answer
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