Question

Derive normal acceleration.​

Answer 1

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Acceleration

(a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt. This allows you to measure how fast velocity changes in meters per second squared (m/s^2). Acceleration is also a vector quantity, so it includes both magnitude and direction.

Answer 2

1 Answer

Position: →r(t)=(x(t)y(t))

Velocity: →v(t)=(x′(t)y′(t))

Acceleration: →a(t)=(x″(t)y″(t))

Tangent Direction: ˆe(t)=→v(t)‖→v(t)‖

Speed Value: vT(t)=ˆe(t)⋅→v(t)

Tangential Acceleration Value: aT(t)=ˆe(t)⋅→a(t)

Normal Acceleration Vector: →aN(t)=→a(t)−aT(t)ˆe(t)