Question

Derive p=vi. calculate electrical power consumed by bulb which has a voltage=2v and current=5ma

Answer 1

Given:-

V = 2v

I = 5ma

Formula used:-

P = V. I

Concept:-

Electrical power of an electric circuit means that the rate of supply of electrical energy to that circuit by the source of electricity.

${\implies{\tt{ \: Electrical power (p) = \frac{Energy \: supplied \: by \: the \: source(W)}{time(t)} = \frac{v.I.t}{t}}}}$

${\implies{\tt{p = v. I}}}$

Solution:-

${\implies{\tt{P = V. I}}}$

${\implies{\tt{ 2 × 5}}}$

${\implies{\tt{P = 10}}}$

$\huge\underline{\underline{\boxed{\mathtt{\color{lawngreen}{P = 10 }}}}}{\color{orange}{\bigstar}}$

Answer 2

$\underline{\sf{\color{gold} Electrical \: power}}$

✿Electrical power of any electrically driven machcine is defined as the rate of consumption of electrical energy with respect to time.

✿ When an electric current l passed through an electrically driven machcine for a time period t , then electrical energy consumed,

W = VIt

Where ,V is the potential difference between the two ends of the resistance of the instrument.

Therefore, electrical power is given by,

$\sf{Electric \: power = \frac{Rate \: of \: supply \: of \: electrical \: energy \: to \: the\: source}{Time} }$

$\sf{\color{indigo}P = \frac{W}{t} }$

$\sf\color{indigo}{\implies P = \frac{VIt}{t} }$

${\boxed{\sf{\color{teal}{\implies P = VI}}}}$

$\rule{300}{2}$

$\huge\underline\mathtt\color{olive}Given:$

• Voltage (V) = 2V
• Current (I) = 5A

$\huge\underline\mathtt\color{olive}ToFind:$

• To calculate electrical power.

$\huge\underline\mathtt\color{olive} Solution:$

$\sf{P = VI}$

$\sf{\implies p = 2 \times 5}$

${\boxed{\sf{\color{plum}{\implies p = 10 \: watt}}}}$

$\huge\underline\mathtt\color{olive}ThankYou$