derive position velocity relation graphically
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EQUATION FOR VELOCITY - TIME RELATION -
Distance traveled = Area of the trapezium OABC
S= {sum of parallel sides }*h/2
s={OA+BC}*DC/2
={U+V}*t/2
From the First equation of motion V=U=at
at= V-U
t=V-U / a
S={ U+ V }*t / 2
= {U+V} * {V-U} / 2a
S= {V+U} * { V -U} / 2a
2as= V^2 - U^2
V^2 = U^2+ 2as
Distance traveled = Area of the trapezium OABC
S= {sum of parallel sides }*h/2
s={OA+BC}*DC/2
={U+V}*t/2
From the First equation of motion V=U=at
at= V-U
t=V-U / a
S={ U+ V }*t / 2
= {U+V} * {V-U} / 2a
S= {V+U} * { V -U} / 2a
2as= V^2 - U^2
V^2 = U^2+ 2as
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