Question

Derive quadratic formula according to quadratic equation.​

Answer 1

is actually derived using the steps involved in completing the square. It stems from the fact that any quadratic function or equation of the form y = a x 2 + b x + c y = a{x^2} + bx + c y=ax2+bx+c can be solved for its roots.

Answer 2

HeRe Is Your Ans

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quadratic formula = { - b ±√(b² - 4ac)}/2a

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ax² + bx + c = 0

ax² + bx = -c

divide both sides by a

x² + (b/a).x = -c/a

add both sides, ( b/2a)²

x² + 2.(b/2a).x + (b/2a)² = -c + (b/2a)²

[ use formula , a² + 2ab + b² = (a + b)² ]

( x + b/2a)² = ( b² - 4ac)/4a²

take square root both sides

(x + b/2a) = ± √(b² -4ac)/2a

x = -b/2a ± √(b² - 4ac)/2a

x = { - b ±√(b² - 4ac)}/2a

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