Derive R = R1+ R2 + R3
Moncheri06:
ARIE
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Answer:
Derivation:
Let there be three resistance R1, R2 and R3 connected in series. A battery of V volts has been applied to the ends of this series combination. Now suppose the potential difference across the resistance R1 is V1, R2 is V2 and R3 is V3.
V = V1+V2+V3.. (1)
Now suppose the total resistance of the combination be R, and the current flowing through the whole circuit be I.
So, applying Ohm's law to the whole circuit,
we get :
V/I = R or V = IR.. (2)
The same current flowing through all three resistances, So by applying Ohm's law three of them separately, we will get
V1 = IR1
V2 = IR2 and
V3 = IR3.. (3)
Now Putting 3 and 2 in equation 1,
we get
IR = IR1+ IR2+IR3
that is IR = I (R1+R2+R3)
R = R1+R2+R3
Hope it is helpful.
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