derive relationship : force = mass × acceleration
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Initial momentum,p1 = mu
Final momentum,p2= MV
Therefore change in momentum = p2- p1= m( v- u
From second law of Motion,
F~ p2- p1/ t
F~ m( v- u)/ t
F~ ma. ( v- u/ t= a)
F = kma ( one unit force is defined as the amount that produces an acceleration of 1 m/ s sq. on a mass of 1 kg
K is constant of proportionality
1 unit f= k *1 kg*1 m/ s sq.
K= 1
Therefore f= ma
Final momentum,p2= MV
Therefore change in momentum = p2- p1= m( v- u
From second law of Motion,
F~ p2- p1/ t
F~ m( v- u)/ t
F~ ma. ( v- u/ t= a)
F = kma ( one unit force is defined as the amount that produces an acceleration of 1 m/ s sq. on a mass of 1 kg
K is constant of proportionality
1 unit f= k *1 kg*1 m/ s sq.
K= 1
Therefore f= ma
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