derive route 3/4 a^2
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Explanation:
Area of Triangle = ½ × base × height
Here, base = a, and height = h
Now, apply Pythagoras Theorem in the triangle.
a2 = h2 + (a/2)2
⇒ h2 = a2 – (a2/4)
⇒ h2 = (3a2)/4
Or, h = ½(√3a)
Now, put the value of “h” in the area of the triangle equation.
Area of Triangle = ½ × base × height
⇒ A = ½ × a × ½(√3a)
Or, Area of Equilateral Triangle = (√3a2)/4
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