Derive rutherford scattering cross-section formula for scattering of alpha particles by heavy atomic nucleus
Answers
Answered by
0
In 1911, Rutherford bombarded a thin foil with alpha particles nd observed the path of alpha particles with the help of circular screen coated with zin sulphate Zns. When an alpha particle struck the screen a flash of light appear therefore he derive following conclusion -
1. Most of alpha particles pass through foil without reflection this indicate most part of atom is hollow or vacant.
2. Few of alpha particles were deflected from their original path through some angle. This indicates atom have +ve charged mass in centre
3. A very less alpha particle were even turned back on their path. This indicates that their is small hard rigid nd +ve charge particles in the atom. This part called nucleus.
HOPE IT HELPS YOU
1. Most of alpha particles pass through foil without reflection this indicate most part of atom is hollow or vacant.
2. Few of alpha particles were deflected from their original path through some angle. This indicates atom have +ve charged mass in centre
3. A very less alpha particle were even turned back on their path. This indicates that their is small hard rigid nd +ve charge particles in the atom. This part called nucleus.
HOPE IT HELPS YOU
Similar questions