Derive s=ut+1/2at2
How??????????????
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we know that, a=dv/dt
=>a×dt =dv, integrating we get,
=>a(t-0)=v-u=>v=u+ at.
Again, dx/dt=(u+at)=>dx=(u+at)dt
=>integrating both sides,
=>x=u(t-0)+a(t²-0)/2=>s=ut+1/2(at²).
=>a×dt =dv, integrating we get,
=>a(t-0)=v-u=>v=u+ at.
Again, dx/dt=(u+at)=>dx=(u+at)dt
=>integrating both sides,
=>x=u(t-0)+a(t²-0)/2=>s=ut+1/2(at²).
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