Question

derive second equation of motion​

Answer 1

→Distance = Average velocity × time

→Average velocity = (u+v)/2

Then s=(u+v)/2×t

According to first equation if motion,

v = u + at

substituting the value of v in above equation

s = (u+u+at)/2 x t

→s = (2u+at)/2 × t

→s = (2ut+at²)/2

→s = 2ut/2 + at²/2

→s=ut+1/2at²

Hence derived.

Answer 2

→Distance = Average velocity × time

→Average velocity = (u+v)/2

Then s=(u+v)/2×t

According to first equation if motion,

v = u + at

substituting the value of v in above equation

s = (u+u+at)/2 x t

→s = (2u+at)/2 × t

→s = (2ut+at²)/2

→s = 2ut/2 + at²/2

→s=ut+1/2at²

Hence derived.