Question

Derive second equation of motion by graphical method​

Answer 1

Distance travelled (s) = Area of figure OABC = Area of rectangle OADC + Area of triangle ABD

s=(1/2AB×BD)+(OA×OC)

Since BD = EA, the above equation becomes

s=(1/2AB×EA)+(u×t)

As EA = at, the equation becomes

s=1/2×at×t+ut

On further simplification, the equation becomes

s=ut+1/2at^2