derive second equation of motion by numerically
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Let the distance travelled by the object be “s”.
We know that,
→Distance = Average velocity × time
→Average velocity = (u+v)/2
Then s=(u+v)/2×t
According to first equation if motion,
v = u + at
substituting the value of v in above equation
s = (u+u+at)/2 x t
→s = (2u+at)/2 × t
→s = (2ut+at²)/2
→s = 2ut/2 + at²/2
→s=ut+1/2at²
Hence derived.
We know that,
→Distance = Average velocity × time
→Average velocity = (u+v)/2
Then s=(u+v)/2×t
According to first equation if motion,
v = u + at
substituting the value of v in above equation
s = (u+u+at)/2 x t
→s = (2u+at)/2 × t
→s = (2ut+at²)/2
→s = 2ut/2 + at²/2
→s=ut+1/2at²
Hence derived.
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