Question

Derive second equation of motion from velocity-time graph.

Answer 1

Heyy Buddy!

At t = 0, initial velocity = u = OA

At t = t, final velocity = v = OC  

The distance S travelled in time t = area of the trapezium OABD

s = (1/2) x (OA + DB) × OD

s = (1/2) x (u + v) × t

Since v = u + at,

s = (1/2) x (u + u + at) × t

s = ut + (1/2) at2

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Answer 2

Answer:

Your answer is

v= u+ at

Where

• v is the final velocity of the body,
• u is the inital velocity of the body
• a is the accleration
• t is the time period

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