Question

Derive:-
$v^{2} = u^{2} + 2as$​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

ANSWER

We will use both of the equations of motion to reach the third equation of motion. This will require a bit of algebra.

S=ut+ 1/2 at²

andv=u+at, include the time variant t

There will be some situations when we do not have any information about time and so it would be a good idea to derive an equation that does not have a t term.

To do this, we rearrange our first equation to get

t=(v−u)/a

and use this to replace t wherever it appears in the second equation. So

S=ut+ 1/2 at²

becomes,

S = u(v−u/a) + 1/2a (v - u/a) ²

2as = 2u(v - u) + ( v - u ) ²

⇒2aS = 2uv−2u² - v² - 2uv - u²

⇒2aS = v²- u²

⇒v2 = u² + 2aS

Explanation:

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