Question

Derive tha equation x=ut+1/2at2

Answer 1

Answer:

 Suppose a body has an initial velocity 'u' and a uniform acceleration 'a' for time 't' so that its final velocity becomes 'v'. Let the distance travelled by the body in this time be 's'. The distance travelled by a moving body in time 't' can be found out by considering its average velocity. Since the initial velocity of the body is 'u' and its final velocity is 'v', the average velocity is given by 

Average velocity =2Initial velocity + Final velocity

That is, Average velocity =2u+v 

Also, Distance travelled = Average velocity × Time 

So, s=(2u+v)×t

From the first equation of motion, we have, v=u+at.

Put this value of v in equation (1), we get: 

s=(2u+u+at)×t

or s=2(2u+at)×t

or  s=22ut+at2

or s=ut+21at2

where, s= distance travelled by the body in time t

u= initial velocity of the body 

and a= acceleration