Question

derive the 3rd equation of motion with explaination​

Answer 1

put it on brainliest bro

Answer 2

Answer:

v2=u2+2as

Explanation:

Derivation of Third Equation of Motion

The third equation of motion is-> v2 = u2 + 2aS

Derivation of Third Equation of Motion by Algebraic Method:

Derivation Of Third Equation Of Motion

Derivation of Third Equation of Motion by Graphical Method:

Derivation Of Equation Of Motion

The total distance travelled, S = Area of trapezium OABC.

So, S=(SumofParallelSides)×Height2=>S=(OA+CB)×OC2

Since, OA = u, CB = v, and OC = t, the above equation becomes->S=(u+v)×t2Now, since t = (v – u)/ a, the above equation can be written as->

S=(u+v)×(v–u)2a

Solving this equation, the third equation of motion is obtained which is->

v2=u2+2aS

Derivation of Third Equation of Motion by Calculus Method:

It is known that,

Derivation Of Equation Of Motion

These were the detailed derivations for equations of motion in the graphical method, algebraic method and calculus method.