derive the archimedes principle ??
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here p is the density and h is the height , A is the cross section!
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Suspend an object in air using spring balance.Let its weight in air be be W1.Fill the measuring cylinder with water upto a crtain level and let its volume be V1.Immerse the object in the measuring cylinder.Note its weight from the spring balance and let it be W2 and let the volume of water left in the cylinder be V2.
Loss of the weight of thw object in water = W1 - W2
Mass = Volume × Density
W= V×D
W1-W2=(V2-V1)×D (Density of water =1g/cm³)
=V2-V1×1
=V2-V1
Weight of loss of an object=Weight of water displaced
Archimedes' principle is verified.
Loss of the weight of thw object in water = W1 - W2
Mass = Volume × Density
W= V×D
W1-W2=(V2-V1)×D (Density of water =1g/cm³)
=V2-V1×1
=V2-V1
Weight of loss of an object=Weight of water displaced
Archimedes' principle is verified.
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