Question

Derive the balancing condition of a Wheatstone’s bridge​

Answer 1

Answer:

The Wheatstone's bridge will be in the balanced condition when the current through the galvanometer is zero. Current will divide in magnitude to I1&I2 to go through resistors P and R. When no current flows through galvanometer current I1 will go through P and Q and current I2 will go through R and S. So, we can write.

Answer 2

Answer:

the wheatstone bridge will be in the balanced condition when the current through the galvanometer is zero then and will divided in magnitude in i1 and i2 to go through resistant p and r when no current flows through galvanometer current i1 will go through p and q and current i2 will go through r&s