Question

derive the distance time relation for an object moving with uniform acceleration.S=ut+2at square.

Answer 1

Area of a trapezium = ½(a+b)h

Giving values as , a= u. b= v

And h= t

Therefore , ½(u+v)t. (1)

As we know v = u + at. (2)

Substituting eq (2) in (1)

½(u + u + at) t

½(2u + at) t

½(2ut + at²)

s = ½(2ut) + ½at²

s = ut + ½at²