Question

Derive the earth's "escape velocity".
GIVE ANSWER ONLY IF YOU KNOW.......
FIRST AND CORRECT ANSWER WILL BE MARKED AS BRAINLIEST M....​

Answer 1

Answer:11.2 km/s is the escape velocity of earth hope this helps you

I hope my answer helps you

Answer 2

Answer:

Initial k.E =1/2 m(v^2)______a

:increase in P.E =0_(_GMm/R)

=GMm/R_____b

comparing a and b

1/2m(v^2)=GMm/R

v^2=2GMm/R

taking square root

v=square root of 2GM/R_______c

As mass of earth is M =g(R^2)/G

GM=gR^2

v=square root of 2gR^2/R

v=square root 2gR

R=6.4×10^6

g=9.8

square root 2×6.4×10^6×9.8

11.2Km/s