Question

derive the equation
(2as=v²-u²)

Full explanation needed !!!!!
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Answer 1

Answer:

See the attachment....

Here velocity taken is average velocity

HOPE IT HELPS...

Answer 2

Step By step Explanation:-

$\sf{ \rm {we \: know \: that \: , }} \\ \bf\underline{ \rm \orange{v = u + at }} \\ \sf\underline{ \rm \orange{or, \:v - u = at }} \\ \\ \sf{ \rm \orange{or, \: t = \frac{v - u}{a} }} \\ \\ \sf{ \rm \red{average \: velocity = \frac{u + v}{2} }} \\ \sf{ \rm \orange{S =( \frac{u + v}{2}) \times t }} \\ \\ \sf\underline{ \rm \red{now \: putting \: the \: value \: of \: t. }} \\ \\ \implies \: \sf{ \rm \orange{S = ( \frac{u + v}{2} )}} \times \sf{ \rm \orange{ (\frac{v - u}{a}) }} \\ \\ \implies \: \sf\underline{ \rm \orange{2as = (v + u) \: (v - u)}} \\ \\ \therefore \: \huge\boxed{\sf{ \rm {2as = {v}^{2} - {u}^{2} }}}$