Question

derive the equation a) v=u+at (b) vsquare -usquare =2as (c) s=ut+1upon 2atsquare

Answer 1

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Answer 2

Heya Hjrkx,
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Here is ur answer:-
(A). v = u + at 
As we know that a = $\frac{v-u}{t}$.
then by transposing ,
         at = v-u 
          v = u + at .   (DERIVED).

(C).s =ut + $\frac{1}{2}$ a $t^{2}$
=average velocity=u+v/2
or, s=distance
s=v^t
so. s= (u+v)t/2
v=u+at
so. s=(u+u+at)t/2
=(2u+at)t/2
=2ut+at sq.
s=ut+1/2at sq. 

(B). Putting value of t in 2nd .
 s = $\frac{u(v-u)}{a }$ + 1/2a$\frac{(v-u)}{a} ^{2 }$
solving this u will get answer.

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