Physics, asked by rraj38163pcdlvk, 11 months ago

Derive the equation for elastic potential energy in a spring​

Answers

Answered by debangshu90hazra
3

Answer:

In order to find the formula for elastic potential energy of a spring we need to look at Hooke's law, which states that the force needed to stretch a spring is proportional to the displacement of the spring. Mathematically this is expressed as F = kx, where x is the displacement and k is the spring constant.

Explanation:

Elastic potential energy formula

Elastic potential energy is the potential energy stored by stretching or compressing an elastic object by an external force such as the stretching of a spring. It is equal to the work done to stretch the spring which depends on the spring constant k and the distance stretched.

According to Hooke’s law, the force applied to stretch the spring is directly proportional to the amount of stretch.

Elastic Potential EnergyIn other words,

Force required to stretch the spring is directly proportional to its displacement. It is given as

F\, =\, -\, kx

Wherein,

k = spring constant

x = displacement

The Elastic Potential Energy Formula of the spring stretched is given as

P.E\, =\, \frac{1}{2}kx^{2}

Where,

P.E = elastic potential energy and it’s expressed in Joule.

MARK AS BRAINLIEST... :)

Answered by Anonymous
6

Elastic potential energy formula

Elastic potential energy is the potential energy stored by stretching or compressing an elastic object by an external force such as the stretching of a spring. It is equal to the work done to stretch the spring which depends on the spring constant k and the distance stretched.

According to Hooke’s law, the force applied to stretch the spring is directly proportional to the amount of stretch.

Elastic Potential EnergyIn other words,

Force required to stretch the spring is directly proportional to its displacement. It is given as

F\, =-kx

Wherein,

k = spring constant

x = displacement

The Elastic Potential Energy Formula of the spring stretched is given as

P.E\, =\, \frac{1}{2}kx^{2}

Where,

P.E = elastic potential energy and it’s expressed in Joule.

Attachments:
Similar questions