Derive the equation for equivalent resistance when three resistances are connected in series.
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Let V be the potential difference across the circuit.
Let the resistors have resistances R1, R2, R3 and potential drops V1, V2 V3 across them respectively.
Let a current I flow through the circuit
According to Ohm's Law,
V = IR , So,
V1 = IR1 ; V2 = IR2 ; V3 = IR3
We know that,
Veq = V1 + V2 + V3
Veq = IR1 + IR2 + IR3
= I (R1 + R2 + R3)
Veq/I = R1 + R2 + R3
Req = R1 + R2 + R3
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i suppose this is the correct explanation
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