Derive the equation for position -velocity relation v2 - u2 = 2as
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From 1st equation of motion,
V = U + AT
Therfore, V - U = AT
We know that
S = (U + V / 2 )×T
∴ S/T = U + V / 2
∴U + V = 2×S/T
∴ U + V = 2S / T
So Substituting eq1 and eq2,
(V - U ) (V + U ) = AT ×2S/T
∴V² - U² = 2AS.
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