Question

Derive the equation Kinetic energy=1/2 mv²

Answer 1

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Answer 2

Hi there dear user ^_^

♧ CHEERFUL TUESDAY ♧

Derivation of KE = mv^2 / 2

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Let us suppose a body of mass 'm' kg at rest acquire velocity 'v' m/s after covering the distance 's' metre (m).

Mass = m kg
Initial velocity (u) = 0 m/s
Final velocity (v) = v m/s
Distance = s metre

W = F × S

W = m × a × s (F = m × a)
________________________

a = v^2 - u^2 / 2s (v^2 = u^2 + 2as)
a = v^2 - 0 / 2s
a = v^2 / 2s
________________________

W = m × v^2 / 2s × s

W = m × v^2 / 2

[ work = energy ]

Kinetic Energy = m × v^2 / 2

..... DERIVED .....

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